Add section - Find identifiers with same symbol

[bendtherules]

Related to #2 .

• Added little note on how to think about symbols and identifiers
• Showed mini example because its just strict equality check
• Added full example which logs when it finds identifiers with the same symbol.
• Updated section title and link in TOC

[itsdouges]

if an identifier is not referenced typeChecker.getSymbolAtLocation(node) would return undefined yeah? should we mention that? 😄

[bendtherules]

No, so think like this - whenever ts finds a identifier, it looks up if a symbol already exists for it and returns that. If not, then it creates a new symbol for it. So, every identifier has a corresponding symbol - it doesn't matter if it appears again in the ast or not. For ex, in our source.ts, inner foo identifier appears only once - but we handle it in just the same way (getsymbol) and can log it. It will give a proper symbol, no undefined.

…

On Fri, 3 Jan, 2020, 4:37 am DOUGES DOES DXMAS, ***@***.***> wrote: ***@***.**** commented on this pull request. ------------------------------ In translations/en/transformer-handbook.md <#3 (comment)> : > -> **TODO** - Is this possible? +Identifiers are created by the parser and are always unique. +Say, if you create a variable `foo` and use it in another line, it will create 2 separate identifiers with the same text `foo`. + +Then, the linker runs through these identifiers and connects the identifiers referring to the same variable with a common symbol (while considering scope and shadowing). Think of symbols as what we intuitively think as variables. + +So, to check if two identifiers refer to the same symbol - just get the symbols related to the identifier and check if they are the same (by reference). if an identifier is *not* referenced typeChecker.getSymbolAtLocation(node) would return undefined yeah? should we mention that? 😄 — You are receiving this because you authored the thread. Reply to this email directly, view it on GitHub <#3>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AAXVDXSDUQHKZUYIUSR2NYDQ3ZXSFANCNFSM4KCGAGHQ> .

[itsdouges]

cool thanks for the explanation :)